13x^2-196x+196=0

Solution for 13x^2-196x+196=0 equation:

13x^2-196x+196=0

a = 13; b = -196; c = +196;
Δ = b2-4ac
Δ = -1962-4·13·196
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-168}{2*13}=\frac{28}{26}
=1+1/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+168}{2*13}=\frac{364}{26}
=14
$